思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
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He also told Ball he may go back into the recording studio to work on "some things that are half-formed or were never finished".。业内人士推荐搜狗输入法2026作为进阶阅读
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BoA wanted a system that would not only automate the posting of transactions